calculation of accuracy for hmc8012 -九游官网下载

question

please can you explain how to calculate accuracy for the digital multimeter hmc8012? i found the tables in the data sheet, but am not sure how to interprete these values.

answer

let's take a dc voltage measurement as example for the calculation. it is important to set the zero point of the measurement section (using the [null] key) for best accuracy. zeroing is done. we measure a voltage of 13,85 v. to perform the calculation we need to refer to the following table:

for a result of 13,85v the 40v range has been selected.

this leads into

  • a standard deviation of 0,02% of the displayed value
    (13,85 v / 100 * 0,02 or 13,85 v * 0,02 % = 2,77 mv)
  • a standard deviation of 0,002% of the selected range
    (40 v / 100 * 0,002 or 40 v * 0,002 % = 0,8 mv)

if the environment temperature range is not within 18-28°c, an additional temperature coefficient must be factored in. in our example we choose the environment temperature to be 30°c, meaning a temperature deviation of 2 k.

for each kelvin below or above those 18-28 °c

  • an addidional temperature coefficient of 0,001% of the displayed value
    (13,85 v / 100 * 0,001 or 13,85 v * 0,001 % = 0,1385 mv)
  • an additional temperature coefficient of 0,0005% of the selected range
    (40 v / 100 * 0,0005 or 40v * 0,005 % = 0,2 mv

must be added.

all in all we have an accuracy of 2,77 mv 0,8 mv 2* 0,1385 mv 2 *0,2 mv = 4,247mv (2 times temperature coefficient each because of 2 k deviation from 28 °c).

result: the real voltage value is in a range between 13.845753 and 13,854247 v.

please find a certainty calculator for the hmc8012 in the attachment of this article. this article was written according to fw version 1.400

name
type
version
date
size
uncertainty_calculation_hmc8012.xlsx
type
faq
version
date
jul 23, 2020
size
44 kb

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